a[x^2+1]=x[a^2+1]

Solution for a[x^2+1]=x[a^2+1] equation:

Simplifying
a[x2 + 1] = x[a2 + 1]

Reorder the terms:
a[1 + x2] = x[a2 + 1]
[1 * a + x2 * a] = x[a2 + 1]
[1a + ax2] = x[a2 + 1]

Reorder the terms:
1a + ax2 = x[1 + a2]
1a + ax2 = [1 * x + a2 * x]

Reorder the terms:
1a + ax2 = [a2x + 1x]
1a + ax2 = [a2x + 1x]

Solving
1a + ax2 = a2x + 1x

Solving for variable 'a'.

Reorder the terms:
1a + ax2 + -1a2x + -1x = a2x + -1a2x + 1x + -1x

Combine like terms: a2x + -1a2x = 0
1a + ax2 + -1a2x + -1x = 0 + 1x + -1x
1a + ax2 + -1a2x + -1x = 1x + -1x

Combine like terms: 1x + -1x = 0
1a + ax2 + -1a2x + -1x = 0

The solution to this equation could not be determined.